Question

aplicando a teorema de tales encontre o valor de x y ou z​

Answer 1

Resposta:

Olá bom dia!

d)

2/3 = x/9

3x = 9*2

3x = 18

x = 18/3

x = 6

e)

x/18 = 5/10

10x = 5*18

10x = 90

x = 90/10

x = 9

f)

9/18 = 15/y

9y = 15*18

9y = 270

y = 270/9

y = 30

x/12 = 9/18

18x = 108

x = 108/8

x = 6

28/6 = z/9

6z = 28*9

6z = 252

z = 252/6

z = 42

Answer 2

Explicação passo-a-passo:

$d) \frac{2}{3} = \frac{x}{9}$

$3x = 18 \\ x = \frac{18}{3}$

$x = 6$

$e) \frac{x}{18} = \frac{5}{10}$

$10x = 90 \\ x = \frac{90}{10}$

$x = 9$

$f) \frac{9}{18} = \frac{15}{y}$

$\frac{1}{2} = \frac{15}{y}$

$y = 2.15 \\ y = 30$

$\frac{x}{12} = \frac{9}{18}$

$\frac{x}{12} = \frac{1}{2}$

$2x = 12 \\ x = \frac{12}{2}$

$x = 6$

$\frac{28}{6} = \frac{z}{9}$

$6z = 9.28 \\ 6z = 252 \\ z = \frac{252}{6}$

$z = 42$