Question

Sendo log x = 4 e log y² = 7, qual o valor log x³ + 2.log x +2.log y?

Answer 1

log x = 4
log y² = 7

log x³ + 2.log x + 2.log y
log x³ + 2.log x + log y²
3log x + 2.log x + log y²
3.4 + 2.4 + 7 = 12 + 8 + 7 = 27

Resposta: 27

Espero ter ajudado.