• Matéria: Matemática
  • Autor: zulu5
  • Perguntado 9 anos atrás

quanto q e 2-[3/5+(1/4+3/2)-1/2?

Respostas

respondido por: Leka555
3
2-[3/5+(1/4+3/2)-1/2=
2-[3/5+(-5/4)-1/2=
2-[- 3/20)-1/2=
2 + 3/20 -1/2 = 
2 3/20 - 1/2 =
63/20 - 1/2 =
53/20 =
2,65

zulu5: obrigadaaaa
respondido por: Joaozaumthinking
1
2-[3/5+(1/4+3/2)-1/2=
(0,250+1,500)
2-[3/5+1,750-0,5]=
2-[0,6+1,750-0,5]
2-[2,350-0,5]=
2-1,850=0,150

Dá 0,150.
Se eu tiver errado,me corrijam :D
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