• Matéria: Matemática
  • Autor: evelynkatherine153
  • Perguntado 3 anos atrás

preciso de ajuda nessa questão!!!!​

Anexos:

Respostas

respondido por: rafames1000
1

Resposta passo a passo:

Quest\~ao\ 02:

A=\left[\begin{array}{cc}2&1\\3&1\end{array}\right] \ e\ B=\left[\begin{array}{cc}3&4\\1&0\end{array}\right]

A)\ \  A.B

C_{11}= 2\times3+1\times 1=6+1=7\\C_{12}= 2\times4+1\times 0=8+0=8\\C_{21}= 3\times3+1\times 1=9+1=10\\C_{22}= 3\times4+1\times 0=12+0=12

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A.B=\left[\begin{array}{cc}7&8\\10&12\end{array}\right]

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B)\ \ B.A

C_{11}= 3\times2+4\times 3=6+12=18\\C_{12}= 3\times1+4\times 1=3+4=7\\C_{21}= 1\times2+0\times 3=2+0=2\\C_{22}= 1\times1+0\times 1=1+0=1

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B.A=\left[\begin{array}{cc}18&7\\2&1\end{array}\right]

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C)\ \ A.B=B.A

\left[\begin{array}{cc}7&8\\10&12\end{array}\right]=\left[\begin{array}{cc}18&7\\2&1\end{array}\right]\ \ \ \Leftarrow\ \ Falso.

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Quest\~ao\ 03:

A=\left[\begin{array}{cc}3&1\\4&-1\end{array}\right] \ e\ B=\left[\begin{array}{cc}2&1\\0&5\end{array}\right]

A)\ \  A.B

C_{11}= 3\times2+1\times 0=6+0=6\\C_{12}= 3\times1+1\times 5=3+5=8\\C_{21}= 4\times2+(-1)\times 0=8-0=8\\C_{22}= 4\times1+(-1)\times 5=4-5=-1

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A.B=\left[\begin{array}{cc}6&8\\8&-1\end{array}\right]

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B)\ \ B.A

C_{11}= 2\times3+1\times 4=6+4=10\\C_{12}= 2\times1+1\times (-1)=2-1=1\\C_{21}= 0\times3+5\times 4=0+20=20\\C_{22}= 0\times1+5\times (-1)=0-5=-5

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B.A=\left[\begin{array}{cc}10&1\\20&-5\end{array}\right]

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C)\ \ A.B=B.A

\left[\begin{array}{cc}6&8\\8&-1\end{array}\right]=\left[\begin{array}{cc}10&1\\20&-5\end{array}\right]\ \ \ \Leftarrow\ \ Falso.


evelynkatherine153: me ajuda em duas questões
evelynkatherine153: de matemática
evelynkatherine153: postei hoje
evelynkatherine153: se puder eu agradeço:)
evelynkatherine153: pode me ajudar?
evelynkatherine153: postei uma questão de física hoje
evelynkatherine153: se puder eu agradeço muito:)
evelynkatherine153: pode me ajudar nas 3 questões que eu mandei?
evelynkatherine153: se puder eu agradeço
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