Question

dada a função f(x)=x²-x calcule
[f(1)+3 f(-1)-5f(3)+f(0)].f(2)

Answer 1

F (x)= x^2 - x
F (1)= (1^2)-1
F (1)= 1-1
F (1)= 0

F (-1)= (-1^2) -1
F (-1)= -1-1
F (-1)= -2

F (3)= (3^2)-2
F (3)= 9-2
F (3)= 7

F (0)= (0^2)-0
F (0)= 0-0=0

F (2)= (2^2)-2
F (2)= 4-2
F (2)=2

[f (1) +3 . f(-1)-5.f (3)+ f (0)]. f (2)

[0+3.(-2)-5.7+0].2
[0-6-35].2
-41.2= -82