Question

Mínimo múltiplo comum de 20,21,e10

Answer 1

$> \: resolucao \\ \\ \geqslant \: mm \: ( \: 20 \: \: . \: \: 21 \: \: . \: \: 10 \: \: ) \\ \\ 20.21.10 \div 2 \\ 10.21.5 \div 2 \\ 5.21.5 \div 3 \\ 5.7.5 \div 5 \\ 1.7.1 \div 7 \\ 1.1.1 \\ \\ \\ mmc > \: 2 \times 2 \times 3 \times 5 \times 7 = 420 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$

Answer 2

$\begin{array}{r r r|l}\sf20&\sf21&\sf10&\sf2\\\sf10&\sf21&\sf5&\sf2\\\sf5&\sf21&\sf5&\sf3\\\sf5&\sf7&\sf5&\sf5\\\sf1&\sf7&\sf1&\sf7\\\sf1&\sf1&\sf1&\!\!\!\overline{~\:\sf2^2\cdot3\cdot5\cdot7=420~}\end{array}$

$\mathbf{MMC(20,21,10)=420 }$