Question

Encontre o termo 10° na progressão geométrica:168,84,42,21,...

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{84}{168} = \frac{1}{2} \\ \\ = = = = = = = = = = = = = \\ \\ > \: o \: 10 \: termo \: da \: pg \\ \\ an = a1 \times q {}^{n - 1} \\ an = 168 \times ( \frac{1}{2} ) {}^{10 - 1} \\ an = 168 \times ( \frac{1}{2} ) {}^{9} \\ an = 168 \times \frac{1}{512} \\ an = \frac{168 \div 8}{512 \div 8} \\ an = \frac{21}{64} \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$