Question

x+1 x-2 1
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6 3 1

Answer 1

$\frac{x+1}{6} + \frac{x-2}{3} \ \textgreater \ \frac{1}{1} \\ \\ mmc=6 \\ \\ \frac{x+1}{6} + \frac{2x-4}{6} \ \textgreater \ \frac{6}{6} \\ \\ x+1+2x-4\ \textgreater \ 6 \\ \\ x+2x\ \textgreater \ 6+4-1 \\ \\ 3x\ \textgreater \ 10-1 \\ \\ 3x\ \textgreater \ 9 \\ \\ x\ \textgreater \ \frac{9}{3} \\ \\ x\ \textgreater \ 3$


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Gannicus
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