Question

log a/3= log 20/3 - log 6/2

Answer 1

Vamos là.

se esta:

log(a/3) = log(20/3) - log(6/2)

log(a/3) = log((20/3)/(3)) = log(20/9)

a/3 = 20/9

a = 20/3

se esta:

log(a)/3 = log(20)/3 - log(6)/2

2log(a)/6 = 2log(20)/6 - 3log(6)/6

2log(a) = 2log(20) - 3log(6)

log(a²) = log(400/216)

a² = 50/27

a = √(50/27)