Question

(x-3)²+2=14??me ajudem

Answer 1

(x-3)²+2=14

(x-3).(x-3)+2=14

x²-3x-3x+9+2=14

x²-6x+11=14

x²-6x+11-14=0

x²-6x-3=0

a = 1; b = -6, c = -3

Δ = b²-4.a.c

Δ = -6²-4.1.(-3)

Δ = 36+12

Δ = 48

x = -b±$\sqrt{48}$ / 2.a

x = -(-6) ±$\sqrt{48}$ / 2.1

x = 6 ±$\sqrt{48}$ / 2

x = 6 ±4$\sqrt{3}$ / 2

x' = 6 + 4$\sqrt{3}$ / 2 (simplifique por 2)

x' = 3 + 2$\sqrt{3}$

x" = 6 - 4$\sqrt{3}$ / 2 (simplifique por 2)

x" = 3 -2$\sqrt{3}$

Espero ter ajudado!!!