Question

equação do 2 grau:

$\times {}^{2} - 4 \times+ 3 = 0$
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Answer 1

x² - 4x + 3 = 0

$x = \frac{ - b + - \sqrt{delta} }{2a}$

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{ - ( - 4) + - \sqrt{ {4}^{2} - 4.1.3 } }{2.1}$

$x = \frac{4 + - \sqrt{16 - 12} }{2}$

$x = \frac{4 + - \sqrt{4} }{2}$

$x = \frac{4 + - 2}{2}$

$x1 = \frac{4 - 2}{2}$

$x1 = \frac{2}{2}$

x' = 1

$x2 = \frac{4 + 2}{2}$

$x2 = \frac{6}{2}$

x'' = 3

S = { 1, 3 }