Question

Como resolvo limit x--> -infinit (√(x²+1))/(x+1)

Answer 1

$\\ \lim_{x \to -\infty} \frac{ \sqrt{x^2+1} }{x+1} \\ \\ \lim_{x \to -\infty} \frac{ \sqrt{x^2( 1+ \frac{1}{x^2} )} }{x(1+ \frac{1}{x} )} \\ \\ \lim_{x \to -\infty} \frac{ \sqrt{x^2(1+ 0) } }{x(1+0)} \\ \\ \lim_{x \to -\infty} \frac{ \sqrt{x^2} }{x} \\ \\ \lim_{x \to -\infty} \frac{|x|}{x} \\ \\ \lim_{x \to -\infty} \frac{-x}{x} = -1$