Question

Seja p(x)= 3x²-x+5, então p(-⅔) vale quanto

Answer 1

Resposta:

Explicação passo a passo:

p(x) = 3x²-x+5

p(-2/3) = 3×(-2/3)²- (-2/3) + 5

p(-2/3) = 3 × 4/6 + 2/3 + 5

p(-2/3) = 4/3 + 2/3 + 5

p(-2/3) = 6/3 + 5

p(-2/3) = 2 +5

p(-2/3) = 7