Question

Gente, definam pra mim os quatro primeiros termos dessa P.A:

a) an = 1+n
b) an= 3n-2
c) an = n/n+1
d) an = n+3/2n
e) an = n²/2
f) an = 1-2n
g) an = 3 elevado a n
h) an = 2 elevado a n/ n

Por favor me ajudem, é para amanhã!

Answer 1

a)a n = 1 + n
a 1 = 1 + 1 = 2
a 2= 1 + 2 = 3
a 3 = 1 + 3 = 4
a 4 = 1 + 4 = 5
b)a n = 3 n - 2
a 1 = 3 . 1 - 2 = 3 - 2 = 1
a 2 = 3 . 2 - 2 = 6 - 2 = 4
a 3 = 3 . 3 - 2 = 9 - 2 = 7
a 4 = 3 . 4 - 2 = 12 - 2 = 10
c) a n = n / n + 1
a 1 = 1 / 1 + 1 = 1/2
a 2 = 2/2+1 = 2/3
a 3 = 3/3+1 = 3/4
a 4 = 4/4 + 1 = 4/5
d)a n = n + 3 / 2n
a 1 = 1 + 3/ 2 . 1 = 4/2 = 2
a 2 = 2 + 3 / 2 . 2 = 5/ 4
a 3 = 3 + 3 / 2.3 = 6/ 6 = 1
a 4 = 4 + 3 / 2 . 4 = 7/ 8
e)a n = n²/2
a 1 = 1²/2  = 1/2
a 2 = 2² / 2 = 4/2 = 2
a 3 = 3² /2 = 9/4
a 4 = 4² / 2 = 16/2 = 8
f)a n = 1 - 2 n
a 1 = 1 - 2.1
a n = 1 - 2 = - 1
a 2= 1 - 2 . 2 = 1 - 4 = - 3
a 3 = 1 - 2 .3 = 1 - 6 = - 5
a 4 = 1 - 2 . 4 = 1 - 8 = -7
g)an = 3^n
a 1 = 3¹ = 3
a 2 = 3² = 9
a 3 = 3³ = 27
a 4 = 3^4 = 81
h)a n = 2^n/n 
a 1 = 2¹/¹ = 2¹ = 2
a 2 = 2²/² = 2¹ = 2
a 3 = 2³/³ = 2¹ = 2
a 4 = 2^4/4 = 2¹ = 2