Question

Determine x e y sabendo que:
$\left[\begin{array}{ccc}x+y&2\\3&1&\end{array}\right] = \left[\begin{array}{ccc}4&x-y\\3&1&\end{array}\right]$

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\left[\begin{array}{cc}\sf x+y&\sf2\\\sf3&\sf1\end{array}\right]=\left[\begin{array}{cc}\sf4&\sf x-y\\\sf3&\sf1\end{array}\right]$

$\mathsf{ \begin{cases}\sf x+y=4\\\sf 2=x-y\end{cases}}$

$\mathsf{ \begin{cases}\sf x+y=4\\\sf x=y+2\end{cases}}$

$\mathsf{y+2+y=4 }$

$\boxed{\boxed{\mathsf{y=1 }}}$

$\mathsf{ x=1+2}$

$\boxed{\boxed{\mathsf{ x=3}}}$

$\mathsf{ Portanto\!\!: ~ \left[\begin{array}{cc}\sf 3+1&\sf2\\\sf3&\sf1\end{array}\right]=\left[\begin{array}{cc}\sf4&\sf 3-1\\\sf3&\sf1\end{array}\right]}$