Question

quantos termos possui a p. g. (3 , 21 ..., 50421

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{21}{3} = 7$

$an = a1 \times q {}^{n - 1} \\ 50421 = 3 \times 7 {}^{n - 1} \\ \frac{50421}{3} = 7 {}^{n - 1} \\ 16807 = 7 {}^{n - 1} \\ 7 {}^{5} = 7 {}^{n - 1} \\ n - 1 = 5 \\ n = 5 + 1 \\ n = 6$

Resposta: PG de 6 termos

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