Question

determine o 8º termo da pg 2, -4 …

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{ - 4}{2} = - 2 \\ \\ = = = = = = = = = = = \\ \\ > \: o \: oitavo \: termo \: da \: pg$

$an = a1 \times q {}^{n - 1} \\ an = 2 \times ( - 2) {}^{8 - 1} \\ an = 2 \times ( - 2) {}^{7} \\ an = 2 \times ( - 128) \\ an = - 256 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$