• Matéria: Matemática
  • Autor: marcellanicoly60
  • Perguntado 2 anos atrás

resolva as questões de inequacoes de 1° grau

a) 4×+5> 2×-3
b)5(×+3)-2(×+1)< 2× +3
c)3(× +1)-2>5(×-1)-3(2×-1)

Respostas

respondido por: hermenegildovalente
0

Resposta:

a)4x+5>2x-3

a)4x+5>2x-3 4x-2x>-3-5

a)4x+5>2x-3 4x-2x>-3-5 2x>-8

a)4x+5>2x-3 4x-2x>-3-5 2x>-8 x>-8/2

a)4x+5>2x-3 4x-2x>-3-5 2x>-8 x>-8/2 x>-4

respondido por: simonesantosaraujo91
0

Resposta:

a)x &gt;  - 4 \\ b)x &lt;  - 10 \\ c)x &gt;  \frac{7}{4}

Explicação passo-a-passo:

 \blue{a)4x + 5 &gt; 2x - 3} \\ 4x + 5 &gt; 2x - 3 \\ 4x + 5 - 2x &gt;  - 3 \\ 4x - 2 &gt;  - 3 - 5 \\ 4x - 2x \\ (4 - 2)x \\ 2x \\ 4x - 2x &gt;  - 3 - 5 \\ 2x &gt;  - 3 - 5 \\  - 3 - 5 \\  - (3 + 5) \\  - 8 \\ 2x &gt;  - 3 - 5 \\ 2x &gt;  - 8 \\ 2x \div 2 &gt;  - 8 \div 2 \\ x &gt;  - 8 \div 2 \\ x &gt;  - 4 \\ 2x &gt;  - 8 \\ x &gt;  - 4 \\ resposta \\ x &gt;  - 4 \\  \\ \blue{b)5(x + 3) - 2(x + 1) &lt; 2x + 3} \\ 5(x + 3) - 2(x + 1) &lt; 2x + 3 \\ 5x + 5 \times 3 - 2(x + 1) &lt; 2x + 3 \\5x + 5 \times 3 - 2x - 2 &lt; 2x + 3  \\5 \times 3  \\ 15 \\ 5x + 5 \times 3 - 2x - 2 &lt; 2x + 3 \\ 5x + 15 - 2x - 2 &lt; 2x + 3 \\5x - 2x  \\(5 - 2)x  \\3x  \\5x + 15 - 2x - 2 &lt; 2x + 3 \\ 3x + 15 - 2 &lt; 2x + 3 \\ 3x + 13 &lt; 2x + 3 \\ 3x + 13 - 2x &lt; 3 \\3x - 2x &lt; 3 - 13 \\3x - 2x  \\(3 - 2)x  \\x  \\ 3x - 2x &lt; 3 - 13 \\ x &lt; 3 - 13 \\ x &lt;  - 10 \\ resposta \\ x &lt;  - 10 \\  \\

 \blue{c)3(x + 1) - 2 &gt; 5(x + 1) - 3(2x - 1)} \\ 3(x + 1) - 2 &gt; 5(x + 1) - 3(2x - 1) \\ 3x + 3 - 2 &gt; 5(x + 1) - 3(2x - 1) \\3x + 3 - 2 &gt; 5x +5 - 3(2x - 1)  \\3x + 3 - 2 &gt; 5x + 5 - 3 \times 2x + 3 \\3 - 2  \\1  \\3x + 3 - 2 &gt; 5x + 5 - 3 \times 2x + 3  \\ 3x + 1 &gt; 5x + 5 - 3 \times 2x + 3 \\ - 3 \times 2  \\ - 6  \\3x + 1 &gt; 5x + 5 - 3 \times 2x + 3 \\3x + 1 &gt; 5 +  + 5 - 6x + 3  \\5x - 6x  \\(5 - 6)x\\ - 1x  \\  - x \\3x + 1 &gt; 5x + 5 - 6x + 3  \\3x + 1 &gt;  - x + 5 + 3  \\5 +3 \\ 8 \\ 3x + 1 &gt;  - x +5 + 3 \\ 3x + 1 &gt;  - x + 8 \\ 3x + 1 + x &gt; 8 \\ 3x + x &gt;  8 - 1 \\ 3x + x \\ (3 + 1)x \\ 4x \\ 3x + x &gt; 8 - 1 \\ 4x &gt; 8 - 1 \\ 4x &gt; 7 \\ 4x \div 4 &gt; 7 \div 4 \\ x &gt; 7 \div 4 \\ \\  x &gt;  \frac{7}{4} \\  \\ 4x &gt; 7 \\  \\ x &gt;  \frac{7}{4} \\ resposta \\  x &gt;  \frac{7}{4}

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