Question

(x+y=20 28 12 X y

como resolver por razão e proporção?​

Answer 1

$\large\bm{\begin{cases}x + y = 20 \\ \\ \dfrac{x}{y} = \dfrac{28}{12} \end{cases}} \\ \\ \\ \large\bm{\begin{cases}x = 20 - y \\ \\ \dfrac{x}{y} = \dfrac{28}{12} \end{cases}} \\ \\ \\ \large\bm{ \dfrac{20 - y}{y} = \dfrac{28}{12} } \\ \\ \large\bm{y = 6} \\ \\ \large\bm{x = 20 - 6} \\ \\\large\bm{x = 14} \\ \\ \bm{\large\boxed{\boxed{  { \large \bm{ \left(x,y\right) = \left(14,6\right) }}}}}$

${\large\boxed{\boxed{  { \large \bm{ Bons~Estudos} }}}}$