Question

Dada a função exponencial f(x)=(1/5)^x calcule o valor numérico de F(2), F(-2)

Answer 1

Resposta:

Substituir x pelos valores dados

$f(x)=(\dfrac{1}5})^X\\ \\\\ f(2)=(\dfrac{1}{5})^2\\ \\\\ \boxed{f(2)=\dfrac{1}{25}}$

$f(-2)=(\dfrac{1}{5})^{-2}\\ \\ \\ f(-2)=(\dfrac{5}{1})^2\\ \\ \\\boxed{ f(-2)=25}$