Question

x²-5=0 ajudem me a resolver em bháskara

Answer 1

( Delta ) = b^2 . 4.a.c

( Delta ) = (-5)^2 . 4. 1. 0

( Delta ) = 25


x' = -(-5) + \/25
2.1
x' = 5+5
2
x' = 10 ÷ 2

x' = 5


x" = -(-5) - \/25
2.1
x" = 5-5
2
x" = 0 ÷ 2

x" = 0

De nada ;)