Question

[H3O^3)= 0,0001 mol/l . Qual a [Oh-]= ?

Answer 1

Dado : Kw = 1 x 10⁻¹⁴

Kw = [ H₃O⁺ ] [ OH⁻]

1 x 10⁻¹⁴ = [ 0,0001] [OH⁻]

[OH⁻ ] = 1 x 10⁻¹⁴ / 0,0001

[OH⁻] = 1 x 10⁻¹⁰ M

espero ter ajudado!