Question

o comprimento final da barra a 20 °C

Answer 1

Dl = Lo x alfa x Dt
Dl= 10 x 12 x 10 -6 x 20
Dl= 200 x 12 x 10 - 6
Dl = 2400 x 10 -6
Dl = 0. 0024 m.
Lfinal = Inicial + delta l
Lfinal = 10 + 0. 0024
Lfinal = 10. 0024