Question

por favor me ajudem a responder essa derivada x^2+ sqrtX

Answer 1

Use a regra:

$\boxed{(x^n)'=n.x^{n-1}}$


$f(x)= x^{2} + \sqrt{x} \\ \\ \boxed{f'(x)=2x+\frac{1}{2 \sqrt{x} }+C}$

Answer 2

$f(x)=x^2+ \sqrt{x} \\f(x)=x^2+x^{ \frac{1}{2} }\\f'(x)=2x+ \frac{1}{2} x^{- \frac{1}{2} }\\ \\\boxed{f'(x)=2x+ \frac{1}{ 2\sqrt{x} } +C}$