Question

1) calcule os limites que tendem ao infinito
a) lim x>oo 3-2x/5x+1 =

b) lim x>oo x^2-4/x+1=

c) lim x>oo 4x+3/3x+2=

d) lim x>oo x^3-1/x^2+1=

e) lim x>oo x^2-3x+4/3x^3+5x^2-6x+2 =

Answer 1

a)lim x->oo. 3-2x/5x+1=>
lim x->oo 3/x-2x/x
------------
5x/x+1/x
lim x->oo. 3/x-2
-----------------------
5+1/x
3 lim x/1-2lim
------------------------
5 lim +1 lim 1/x


lim x->oo. -2/5

espero ter ajudado