Question

Me Ajudem nessa questão?
4) (cancelando a √ x+1 √2x-3)² = (2)²

x+1 + √ 2x-3 = 4
√ 2x -3 = 4
( √ 2x-3 )² (3 - x) ²

Answer 1

x+1+√2x-3=4
√2x-3=4-x-1
(√2x-3)^2=(3-x)^2
2x-3=3^2-2•3 (-x)+(-x)^2
2x-3=9+9x+x^2
2x-9x=12+x^2
x^2+7x+12=0(bascara)
delta=7^2-4•1•12
delta=14-48
nao existe delta
S=[nao existe]