Question

determine; C=(cij) 3×2, tal que cij=(i-j)^3

Answer 1

c11=(1-1)³=0³=0
c12=(1-2)=-1³=-1
c21=(2-1)³=1³=1
c22=(2-2)³=0³=0
c31=(3-1)³=2³=8
c32=(3-2)³=1³=1

C= | 0 -1 |
| 1 0 |
| 8 1 |