• Matéria: Matemática
  • Autor: EdvanGB
  • Perguntado 9 anos atrás

qual a derivada de 1+3r2)/r2-r

Respostas

respondido por: andresccp
0
f(r)= \frac{1+3r^2}{r^2-r}

usando a regra do quociente
\boxed{\boxed{\left( \frac{U}{V}\right)' =  \frac{U'*V-U*V'}{V^2} }}

aplicando isso
f'(r)= \frac{(1+3r^2)'*(r^2-r) - (1+3r^2)*(r^2-r)'}{(r^2-r)^2} \\\\ f'(r)= \frac{(0+3*2r^{2-1})*(r^2-r) - (1+3r^2)*(2r^{2-1}-r^{1-1})}{(r^2-r)^2} \\\\ f'(r)= \frac{(6r)*(r^2-r) - (1+3r^2)*(2r-1)}{(r^2-r)^2} \\\\f'(r)= \frac{(6r^3-6r^2)-(6r^3 -3r^2+2r-1)}{(r^2-r)^2} \\\\\boxed{\boxed{f'(r)= \frac{-3r^2-2r+1}{(r^2-r)^2} }}

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