Question

dada a expressao x=-b-+vb2-4.a.c/2.asendo a=1,b=-7 e c=10,o valor numerico de x e

Answer 1

         $x= \frac{-b+/- \sqrt{b^2-4.a.c} }{2a} \\ \\ a=1 \\ b=-7 \\ c=10 \\ \\ x= \frac{-(-7)+/- \sqrt{(-7)^2-4(1)(10)} }{2.1} \\ \\ x= \frac{7+/- \sqrt{49-40} }{2} \\ \\ x= \frac{7+/- \sqrt{9} }{2} \\ \\ x= \frac{7+/-3}{2} \\ \\ x1= \frac{7-3}{2} = \frac{4}{2} =2 \\ \\ x2= \frac{7+3}{2} = \frac{10}{2} =5$