Question

dada a funcao h(x)=x²-x, determine h(5)+h(1/2)

Answer 1

$h(x)=x^2-x\\ \\h(5)=5^2-5=25-5=20\therefore h(5)=20\\ \\h(\frac{1}{2})=(\frac{1}{2})^2-(\frac{1}{2})=\frac{1}{4}-\frac{1}{2}=\frac{1}{4}-\frac{2}{4}=\frac{1-2}{4}=-\frac{1}{4}\therefore h(\frac{1}{2})=-\frac{1}{4}\\ \\h(5)+h(\frac{1}{2})=20+(-\frac{1}{4})=20-\frac{1}{4}=\frac{80}{4}-\frac{1}{4}=\frac{80-1}{4}=\frac{79}{4}$