Question

Sendo sec x=7/3, determine o valor de cotg x

Answer 1

sec²x=1+tg²x     tg²x=1- sec²x       tg²x= (7/3)²-1=40/9    tgx=2√5.2/3=2√10/3

cotg x=  1/tgx= 1/2√10/3     cotg x=3/2√10