• Matéria: Matemática
  • Autor: francieleregina
  • Perguntado 9 anos atrás

 resolva as equações o 2¨grau 

 

x²+2x+1= 0

 

 

x²+20x= 300 

 

 

x²+5x= 6

Respostas

respondido por: Eriivan
5
a )

x^2-2x+1=0\\\Delta=2^2-4.1.1\\\Delta=0\\
\\x= \frac{-b}{2a} ~\to~x=-1

b )

x^2+20x=300\\x^2+20x-300=\\\Delta=20^2-4.1.(-300)\\\Delta=1600

x= \frac{-20\pm \sqrt{1600} }{2} ~\to~ \frac{-20\pm40}{2} ~\to~x=-10\pm20

x'=10~~~~x''=-30

c )

x^2+5x=6\\x^2+5x-6=0\\\Delta=5^2-4.1.(-6)\\\Delta=49

x= \frac{-5\pm \sqrt{49} }{2} ~\to~x= \frac{-5\pm7}{2}

x'=1

x''=-6

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