• Matéria: Matemática
  • Autor: peixerisabela
  • Perguntado 9 anos atrás

ME AJUDEM PFVRR
-5/4-(-1/2)2 Sobre (2/3)-¹

Respostas

respondido por: LuanaSC8
1
\dfrac{- \dfrac{5}{4} -\left(-\dfrac{1}{2} \right)^2  }{ \dfrac{2}{3}^{-1} } \to~~~~  \dfrac{- \dfrac{5}{4} -\left(\dfrac{1}{4} \right)  }{ \dfrac{3}{2}^1 } \to~~~~ \dfrac{- \dfrac{5}{4} -\dfrac{1}{4} }{ \dfrac{3}{2} } \to~~~~\\\\\\\\ \dfrac{\dfrac{-5-1}{4} }{ \dfrac{3}{2} } \to~~~~  \dfrac{\dfrac{-6}{4} }{ \dfrac{3}{2} } \to~~~~  \dfrac{-6}{4} \times \dfrac{2}{3}\to~~~~  \dfrac{-12}{12}\to~~~~ \large\boxed{~-1~}
respondido por: Anônimo
0

 \frac{-  \frac{5}{4} - (- \frac{1}{2})^{2}  }{ \frac{2}{3}^{-1}  }

\frac{- \frac{5}{4} - \frac{1}{4}}{ \frac{2}{3}^{-1} }

\frac{- \frac{6}{4}}{ \frac{2}{3}^{-1} }

{- \frac{6}{4}. \frac{2}{3} }

= -1

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