Question

Simplifique os radicais e efetue as operações

 

√8+√32

√27+√3

3√5+√20

2√2+√18

Answer 1

$\sqrt{8} + \sqrt{32} = \sqrt{4.2} + \sqrt{16.2} = 2\sqrt{2} + 4\sqrt{2} =6 \sqrt{2}$

$\sqrt{27} + \sqrt{3} = \sqrt{9.3} + \sqrt{3} = 3\sqrt{3} + \sqrt{3} =4 \sqrt{3}$

$3\sqrt{5} + \sqrt{20} = 3\sqrt{5} + \sqrt{4.5} = 3\sqrt{5} + 2\sqrt{5} =5 \sqrt{5}$

$2\sqrt{2} + \sqrt{18} = 2\sqrt{2} + \sqrt{9.2} = 2\sqrt{2} + 3\sqrt{2} =5 \sqrt{2}$

Answer 2

$a) \sqrt{8} +\sqrt{32} =\sqrt{4\cdot2} +\sqrt{16\cdot2} =\sqrt{4}\cdot\sqrt{2} +\sqrt{16}\cdot\sqrt{2} \\=2\sqrt{2} +4\sqrt{2} =6\sqrt{2}\\ \\ b) \sqrt{27}+\sqrt{3}=\sqrt{9\cdot3}+\sqrt{3}=\sqrt{9}\cdot\sqrt{3}+\sqrt{3}=3\sqrt{3}+\sqrt{3}=4\sqrt{3}\\ \\ c) 3\sqrt{5}+\sqrt{20}=3\sqrt{5}+\sqrt{4\cdot5}=3\sqrt{5}+\sqrt{4}\cdot\sqrt{5}=3\sqrt{5}+2\sqrt{5}=5\sqrt{5}\\ \\\ d) 2\sqrt{2}+\sqrt{18}=2\sqrt{2}+\sqrt{9\cdot2}=2\sqrt{2}+\sqrt{9}\cdot\sqrt{2}= 2\sqrt{2}+3\cdot\sqrt{2}= 5\sqrt{2}$