Question

3y+1 ÷ 2 = y² - 1 ÷ 3

Answer 1

Olá Julio

(3y + 1)/2 = (y² - 1)/3

3*(3y + 1) = 2*(y² - 1)

9y + 3 = 2y² - 2

2y² - 9y - 5 = 0

delta
d² = 81 - 40 = 121
d = 11

y1 = (9 + 11)/4 = 20/4 = 5
y2 = (9 - 11)/4 = -2/4 = -1/2