Question

equações do segundo grau:

a) x²+14x+48=0
b)x²+3x-10=0

Answer 1

A)Δ=b²-4.a.c

Δ=14²-4.1.48
Δ=196-192
Δ=4

$\frac{-14+-2}{2}$ 

x'=-14+2/2=-12/2=-6
x''=-14-2/2=-16/2=8

B)Δ=3²-4.1-10
Δ=9+40
Δ=49

$\frac{-3+-7}{2}$

x'=-3+7/2=4/2=2
x''=-3-7/2=-10/2=-5