• Matéria: Matemática
  • Autor: Anônimo
  • Perguntado 9 anos atrás

<var>A=\left[\begin{array}{ccc}1&amp;5&amp;-3\\-1&amp;7&amp;0\\2&amp;4&amp;9\end{array}\right]</var>

Respostas

respondido por: Anônimo
1
Como você pediu no chat ;)

Resolverei por laplace.

A=\begin{bmatrix}1&amp;5&amp;-3\\-1&amp;7&amp;0\\2&amp;4&amp;9\end{bmatrix}

det(A)=(-1)^{1+1}*a_{1,1}*\begin{vmatrix}7&amp;0\\4&amp;9\end{vmatrix}+(-1)^{1+2}*a_{2,1}*\begin{vmatrix}5&amp;-3\\4&amp;9\end{vmatrix}+\\(-1)^{1+3}*a_{3,1}*\begin{vmatrix}5&amp;-3\\7&amp;0\end{vmatrix}

det(A)=a_{1,1}*\begin{vmatrix}7&amp;0\\4&amp;9\end{vmatrix}-a_{2,1}*\begin{vmatrix}5&amp;-3\\4&amp;9\end{vmatrix}+a_{3,1}*\begin{vmatrix}5&amp;-3\\7&amp;0\end{vmatrix}

det(A)=\begin{vmatrix}7&amp;0\\4&amp;9\end{vmatrix}+\begin{vmatrix}5&amp;-3\\4&amp;9\end{vmatrix}+2*\begin{vmatrix}5&amp;-3\\7&amp;0\end{vmatrix}

det(A)=63+57+2*21

det(A)=63+57+42

\boxed{\boxed{det(A)=162}}
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