Question

X2+3y-10=0

X2+14×+24=0

(2×-+)•(×-4)=(7+×)•(-×-2)

Answer 1

x²+3x-10 = 0
∆ = 3²-4.1.(-10)
∆= 9+40 =49 =7²

x = (-3±√7²)/2
x = (-3±7)/2—> x=2 , x=-5

x²+14x+24=0
∆=14²-4.1.24
∆= 196-96 = 100 = 10²

x= (-14±√10²)/2
x = (-14±10)/2—› x=-2 , x=-12

espero ter ajudado ,abs