Question

RESOLVA
A)√48-√12+√300

B)3√8+5√2+√32

C)2√27+5√243

D)4√20+2√45

E)√27×2√45

F)4√3Y⁸+2√27Y⁸- 4√48Y⁸=

Answer 1

A)√48-√12+√300 = V2^4.3 - V2^2.3 + V3.10^2 = 2^2V3-2V3+10V3
                           ==> 4V3-2V3+10V3 ==> 12V3

B)3√8+5√2+√32 = 3V2^2.2 + 5V2 + V2^4.2 = 3.2V2 +5V2 + 2^2V2
                           ==> 6V2+5V2 +4V2 ==> 15V2

C)2√27+5√243 = 2V3^2.3 + 5V3^4.3 = 2.3V3 + 5.3^2V3= 6V3+45V3 ==> 51V3

D)4√20+2√45 = 4V2^2.5+2V3^2.5= 4.2V5+2.3V5=8V5+6V5==> 14V5
                                             
E)√27×2√45 = 2V3^2.3.3^2.5 = 2.3^2V3.5 ==> 18V15

F)4√3Y⁸+2√27Y⁸- 4√48Y⁸== 4y.V3y + 2.3y.V3y - 4.2^2y.V3y
==> 4y.V3y + 6y.V3y -16y.V3y
                          ==> - 6y,V3