Question

calcule a soma dos termos da pg(1,2,......1024)

Answer 1

a1 = 1
an = 1024
q = 2/1==> q = 2
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an =  a1.q^(n-1)

1. 2^(n-1) = 1024 ==> 2^(n-1) = 2^10

n-1 = 10 ==> n = 10+1 ==> n = 11
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Sn = a1(q^n – 1)
         q – 1

S11 = 1.(2^11 – 1)
               2 – 1

S11 = 2^10  ==> S11 = 2^10
            1






Sn = a1(q^n – 1)
         q – 1