Question

Se a é = 0,666...,B = 1,333... e C = 0,141414 então ab elevado a  -1 + c é igual a:

 

Answer 1

a = 0,666...= 6/9 = 2/3
B = 1,333...= 1+3/9 = 12/9 =4/3 
 C = 0,141414 = 14/99 
então :
ab-¹ + c=
(2/3.4/3)-¹ + 14/99 =
 (8/9)-¹ + 14/99 =
 9/8 + 14/99 = ---mmc(8,99)=792
891/792 + 112/792 = 1003/792

Answer 2

$(\frac{2}{3} * \frac{4}{3})^{-1} + \frac{14}{99} \\ \\ \frac{3}{2} * \frac{3}{4} + \frac{14}{99} \\ \\ \frac{9}{8} + \frac{14}{99} => \frac{1003}{792}$