Question

3X²-2x-1=0 formula de baskara alguem me ajuda

Answer 1

Oi 

a=3
b=-2
c=-1

Δ=b²-4ac
Δ=(-2)²-4.3.(-1)
Δ=4+12
Δ=16

x= (-b+-√Δ) / 2a

x= (-(-2)+-√16) /2.3

x=(2+-4) / 6

x'=6/6  = 1

x''= -2/6 = -1/3

Comenta depois

Answer 2

delta = (b*b) - 4*a*c -> delta = (-2*-2) - 4*a*c -> delta = 4 - 4*(3)*(-1)
delta = 4 + 12 -> delta = 16;

x = ( -(b) ± √delta ) / ( 2*(a) );

x = ( -(-2) ± √16 )/ 2 * (3) -> x = ( 2  ± 4 ) / 6;

x' = ( 2  + 4 ) / 6 -> x' = 1;
x'' =  ( 2  - 4 ) / 6 -> x'' = -1/3;