Question

resolva a seguinte equaçao 25x ao quadrado=20x-4 me ajudem por favor

Answer 1

Boa noite!

Solução!

$25 x^{2} =20x-4$

$25 x^{2} -20x+4=0\\\\\\ x= \dfrac{-b\pm \sqrt{b^{2} -4.a.c } }{2.a}\\\\\\\ x= \dfrac{-(-20)\pm \sqrt{(20)^{2} -4.25.4 } }{2.25}\\\\\\\ x= \dfrac{20\pm \sqrt{400 -400 } }{50}\\\\\\\ x= \dfrac{20\pm \sqrt{0 } }{50}\\\\\\\ x= \dfrac{20\pm 0 }{50}\\\\\\\ Duas~~ raizes~~ iguais\\\\\\\\\ x_{1}= x_{2}= \frac{20}{50} \\\\\\\\ x_{1}= x_{2}= \frac{2}{5} \\\\\\\\\\\\\\\ \boxed{Resposta:x_{1}= x_{2}= \frac{2}{5} }$

Boa noite!
Bons estudos!