Question

x^2+9x+8=0 ????????????

Answer 1

resolvendo a bhaskara temos que x' = -1/2 e x''= -15/2

Answer 2

x² + 9x + 8 = 0

Δ= b²- 4ac

Δ= 9² - 4x1x8

Δ= 81 - 32

Δ=49

x= -b ±√Δ/2a

x=-9 ± √49/2x1

x= -9±7/2

x'= -9 + 7/2

x'=-2/2

x'=-1

x''= -9-7/2

x''=-16/2

x''= -8

Logo as possíveis raízes são -1 e -8