Question

Parte real do numero complexo 2+3i/2-3i é :

Answer 1

$\frac{2+3i}{2-3i}= \frac{(2+3i)(2+3i)}{(2-3i)(2+3i)}=  \frac{4+12i+ 9i^{2} }{4-9i^{2} }$=
$\frac{4+12i+9.(-1)}{4-9.(-1)} = \frac{x4+12i-9}{4+9}$
$\frac{-5+12i}{13}= -\frac{5}{13}+ \frac{2i}{13}$

logo a parte real é:$-\frac{13}{5}$