Question

alguém sabe essa questão pfv?

Answer 1

$f(x) = \frac{x-1}{x+1} \\\\ f(3) = \frac{3-1}{3+1} = \frac{2}{4} = \frac{1}{2} \\\\ f( \frac{1}{3}) = \frac{ \frac{1}{2}-1 }{ \frac{1}{2} +1} = - \frac{1}{3} \\\\ f(- \frac{1}{3}) = \frac{- \frac{1}{3} -1}{- \frac{1}{3} +1} = -2$

Portanto, f(f(f(3))) = -2