Question

Me ajudem

B) X-3=2√x
Ç)√5+√3x-2=3
D) √13+⁴√12-x=4

Answer 1

X-3=2√x

(x-3)²=4*x

x²-6x+9=4x

x²-10x+9=0

usando bhaskara temos

Δ=b²-4ac
Δ=100-36
Δ=64

x'=(-b+√Δ)/2a
x'=10+8/2=9

x''=(-b-√Δ)/2a
x''=10-8/2=1

as raízes são x'=9 e x''=1