Dados log 2 = 0,301 e log 3 = 0,477. Mudando para a base decimal, calcule. a)log60 na base 2 / b) log 3 na base 2/ c) log 20 na base 9 / d)log 12 na base 6/ e) log30 na base 6
Respostas
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a)
(log 60)/(log 2)
(log 3*2*10)/0,301
(log 3+log 2+log 10)/0,301
(0,477+0,301+1)/0,301...
b)
(log 3)/(log 2)
0,477/0,301
c)
(log 20)/(log 9)
(log 2*10)/(log 3*3)
(log 2+log 10)/(2log 3)
(0,301 + 1)/(2*0,477)...
d)
(log 12)/(log 6)
(log 3*2*2)/(log 2*3)
(log 3+log 2+log 2)/(log 2 +log 3)
(0,477 + 2*0,301)/(0,301+0,477)...
e)
(log 30)/(log 6)
(log 3*10)/(log 2*3)
(log 3+log 10)/(log 2+log 3)
(0,477 + 1)/(0,301 + 0,477)...
(log 60)/(log 2)
(log 3*2*10)/0,301
(log 3+log 2+log 10)/0,301
(0,477+0,301+1)/0,301...
b)
(log 3)/(log 2)
0,477/0,301
c)
(log 20)/(log 9)
(log 2*10)/(log 3*3)
(log 2+log 10)/(2log 3)
(0,301 + 1)/(2*0,477)...
d)
(log 12)/(log 6)
(log 3*2*2)/(log 2*3)
(log 3+log 2+log 2)/(log 2 +log 3)
(0,477 + 2*0,301)/(0,301+0,477)...
e)
(log 30)/(log 6)
(log 3*10)/(log 2*3)
(log 3+log 10)/(log 2+log 3)
(0,477 + 1)/(0,301 + 0,477)...
Brenow98:
esses "..." significam que vc deve terminar apenas de resolver a conta.
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