Question

Resolva essa biquadrada = (x²-6)²=x²

Answer 1

(x² - 6)² = x²
x⁴ - 12x²+ 36 = x²
x⁴ - 12x² - x² + 36 = 0
x⁴ - 13x² + 36 = 0>> y² - 13y + 36 = 0

bhaskara:
b² - 4ac
-13² - 4.1.36
 169 - 144
25 = Δ

-b +/- √Δ /2a
-(-13) +/- √25/2.1
13 +/- 5 / 2

y1 = 18 / 2 = 9
y2 = 8/2 = 4
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x1 = √y1 = √9 = 3
x2 = -√y1 = -√9 = -3
x3 = √y2 = √4 = 2
x4 = -√y2 = -√4 = -2