Question

resolva a equação utilizando o Bhaskara

Answer 1

- 4x² + 4x - 1 = 0
a = -4
b = 4
c = -1 

Δ = b² – 4 .a .c
Δ = 4² - 4(-4)(-1)
Δ = 16 - 16
Δ = 0

x = – b ± √Δ / 2a
x = -4 ± √0 / 2.(-4)
x = -4 / -8
x = 1/2

S = {1/2}

Answer 2

Resposta:

S = {1/2}

Explicação passo-a-passo:

$-4x^{2} +4x-1=0\:\times(-1)\\4x^{2} -4x+1=0$

$a=4\\b=(-4)\\c=1$

$\Delta=b^{2}-4ac\\\Delta=(-4)^{2}-4\times4\times1\\\Delta=16-16\\\Delta=0$

$x=\frac{-b\pm\sqrt{\Delta} }{2a}\\ \\x=\frac{-(-4)\pm\sqrt{0} }{2\times4} \\\\x=\frac{4\pm0}{8}$

$x_{1} =\frac{4+0}{8} =\frac{4^{\div4}}{8} =\frac{1}{2} \\\\x_{2} =\frac{4-0}{8} =\frac{4^{\div4}}{8} =\frac{1}{2}$

S = {1/2}